※ 引述《a00raso (安安)》之銘言：

: 想要知道離心機的rpm和離心力大小(幾g)之間的關係～～
: 我找到網路上面的資料公式是：
: G＝1.11＊10^(-5)＊R＊(rpm)^2
: R的單位是cm
: 不過就是推算不出來這個式子＠＠
: 還是這只是實驗出來的結果～
: 無法用理論去計算？
: 謝謝～～

(1) Because rpm is revolution(s) per minute,
rpm = (w/(2Pi))*60 where w is radian/sec

Thus, w=(Pi/30)*rpm

(2) a=rw^2 (because a=(v^2)/r, & v=rw)

(3) RCF (relative centrifugal force) is defined as
RCF= (a/g)= (rw^2)/980 = {r[(Pi/30)*rpm]^2}/980
=1.119* 10^(-5) * (rpm)^2 * r
done!

P.S. In fact, the question of this sort was asked about two years ago, and I
replied to it at that time

--
" I was born not knowing and have only had a little time to change that
here and there" --- Richard P. Feynman

--
※ 發信站: 批踢踢實業坊(ptt.cc) 
◆ From: 140.128.65.230