小弟在執行php網頁的時候，出現下面錯誤訊息
    You have an error in your SQL syntax; check the manual that corresponds
    to your MySQL server version for the right syntax to
    use near 'leave WHERE level=2 and id='tom'' at line 1

    那我回去查原來的程式碼為
    <?php
mysql_select_db($database_admin, $admin);
$query_Recordset2 = "SELECT * FROM leave WHERE level=2 and id=$PHP_AUTH_USER ";
$Recordset2 = mysql_query($query_Recordset2, $admin) or die(mysql_error());
$row_Recordset2 = mysql_fetch_assoc($Recordset2);
$totalRows_Recordset2 = mysql_num_rows($Recordset2);
?>
    不曉得出什麼問題ㄟ，請教各位前輩

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